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NEW QUESTION # 24
Company A has recently acquired company B. The Snowflake deployment for company B is located in the Azure West Europe region.
As part of the integration process, an Architect has been asked to consolidate company B's sales data into company A's Snowflake account which is located in the AWS us-east-1 region.
How can this requirement be met?
- A. Build a custom data pipeline using Azure Data Factory or a similar tool to extract the sales data from company B's Snowflake account. Transform the data, then load it into company A's Snowflake account.
- B. Migrate company B's Snowflake deployment to the same region as company A's Snowflake deployment, ensuring data locality. Then perform a direct database-to-database merge of the sales data.
- C. Export the sales data from company B's Snowflake account as CSV files, and transfer the files to company A's Snowflake account. Import the data using Snowflake's data loading capabilities.
- D. Replicate the sales data from company B's Snowflake account into company A's Snowflake account using cross-region data replication within Snowflake. Configure a direct share from company B's account to company A's account.
Answer: D
Explanation:
The best way to meet the requirement of consolidating company B's sales data into company A's Snowflake account is to use cross-region data replication within Snowflake. This feature allows data providers to securely share data with data consumers across different regions and cloud platforms. By replicating the sales data from company B's account in Azure West Europe region to company A's account in AWS us-east-1 region, the data will be synchronized and available for consumption. To enable data replication, the accounts must be linked and replication must be enabled by a user with the ORGADMIN role. Then, a replication group must be created and the sales database must be added to the group. Finally, a direct share must be configured from company B's account to company A's account to grant access to the replicated data. This option is more efficient and secure than exporting and importing data using CSV files or migrating the entire Snowflake deployment to another region or cloud platform. It also does not require building a custom data pipeline using external tools.
References:
* Sharing data securely across regions and cloud platforms
* Introduction to replication and failover
* Replication considerations
* Replicating account objects
NEW QUESTION # 25
Which technique will efficiently ingest and consume semi-structured data for Snowflake data lake workloads?
- A. Information schema
- B. Schema-on-write
- C. Schema-on-read
- D. IDEF1X
Answer: C
Explanation:
Option C is the correct answer because schema-on-read is a technique that allows Snowflake to ingest and consume semi-structured data without requiring a predefined schema. Snowflake supports various semi-structured data formats such as JSON, Avro, ORC, Parquet, and XML, and provides native data types (ARRAY, OBJECT, and VARIANT) for storing them. Snowflake also provides native support for querying semi-structured data using SQL and dot notation. Schema-on-read enables Snowflake to query semi-structured data at the same speed as performing relational queries while preserving the flexibility of schema-on-read.
Snowflake's near-instant elasticity rightsizes compute resources, and consumption-based pricing ensures you only pay for what you use.
Option A is incorrect because IDEF1X is a data modeling technique that defines the structure and constraints of relational data using diagrams and notations. IDEF1X is not suitable for ingesting and consuming semi-structured data, which does not have a fixed schema or structure.
Option B is incorrect because schema-on-write is a technique that requires defining a schema before loading and processing data. Schema-on-write is not efficient for ingesting and consuming semi-structured data, which may have varying or complex structures that are difficult to fit into a predefined schema. Schema-on-write also introduces additional overhead and complexity for data transformation and validation.
Option D is incorrect because information schema is a set of metadata views that provide information about the objects and privileges in a Snowflake database. Information schema is not a technique for ingesting and consuming semi-structured data, but rather a way of accessing metadata about the data.
References:
* Semi-structured Data
* Snowflake for Data Lake
NEW QUESTION # 26
What Snowflake features should be leveraged when modeling using Data Vault?
- A. Data needs to be pre-partitioned to obtain a superior data access performance
- B. Scaling up the virtual warehouses will support parallel processing of new source loads
- C. Snowflake's ability to hash keys so that hash key joins can run faster than integer joins
- D. Snowflake's support of multi-table inserts into the data model's Data Vault tables
Answer: B
NEW QUESTION # 27
Which feature provides the capability to define an alternate cluster key for a table with an existing cluster key?
- A. Search optimization
- B. External table
- C. Materialized view
- D. Result cache
Answer: C
NEW QUESTION # 28
A company has an inbound share set up with eight tables and five secure views. The company plans to make the share part of its production data pipelines.
Which actions can the company take with the inbound share? (Choose two.)
- A. Create a table stream on the shared table.
- B. Create a table from the shared database.
- C. Grant modify permissions on the share.
- D. Create additional views inside the shared database.
- E. Clone a table from a share.
Answer: D,E
Explanation:
These two actions are possible with an inbound share, according to the Snowflake documentation and the web search results. An inbound share is a share that is created by another Snowflake account (the provider) and imported into your account (the consumer). An inbound share allows you to access the data shared by the provider, but not to modify or delete it. However, you can perform some actions with the inbound share, such as:
* Clone a table from a share. You can create a copy of a table from an inbound share using the CREATE TABLE ... CLONE statement. The clone will contain the same data and metadata as the original table, but it will be independent of the share. You can modify or delete the clone as you wish, but it will not reflect any changes made to the original table by the provider1.
* Create additional views inside the shared database. You can create views on the tables or views from an inbound share using the CREATE VIEW statement. The views will be stored in the shared database, but they will be owned by your account. You can query the views as you would query any other view in your account, but you cannot modify or delete the underlying objects from the share2.
The other actions listed are not possible with an inbound share, because they would require modifying the share or the shared objects, which are read-only for the consumer. You cannot grant modify permissions on the share, create a table from the shared database, or create a table stream on the shared table34.
References:
* Cloning Objects from a Share | Snowflake Documentation
* Creating Views on Shared Data | Snowflake Documentation
* Importing Data from a Share | Snowflake Documentation
* Streams on Shared Tables | Snowflake Documentation
NEW QUESTION # 29
Loading data using snowpipe REST API is supported for external stage only
- A. FALSE
- B. TRUE
Answer: A
NEW QUESTION # 30
Which steps are recommended best practices for prioritizing cluster keys in Snowflake? (Choose two.)
- A. Choose lower cardinality columns to support clustering keys and cost effectiveness.
- B. Choose TIMESTAMP columns with nanoseconds for the highest number of unique rows.
- C. Choose cluster columns that are most actively used in selective filters.
- D. Choose cluster columns that are actively used in the GROUP BY clauses.
- E. Choose columns that are frequently used in join predicates.
Answer: C,E
NEW QUESTION # 31
An Architect needs to grant a group of ORDER_ADMIN users the ability to clean old data in an ORDERS table (deleting all records older than 5 years), without granting any privileges on the table. The group's manager (ORDER_MANAGER) has full DELETE privileges on the table.
How can the ORDER_ADMIN role be enabled to perform this data cleanup, without needing the DELETE privilege held by the ORDER_MANAGER role?
- A. This scenario would actually not be possible in Snowflake - any user performing a DELETE on a table requires the DELETE privilege to be granted to the role they are using.
- B. Create a stored procedure that can be run using both caller's and owner's rights (allowing the user to specify which rights are used during execution), and grant USAGE on this procedure to ORDER_ADMIN. The ORDER_MANAGER role owns the procedure.
- C. Create a stored procedure that runs with caller's rights, including the appropriate "> 5 years" business logic, and grant USAGE on this procedure to ORDER_ADMIN. The ORDER_MANAGER role owns the procedure.
- D. Create a stored procedure that runs with owner's rights, including the appropriate "> 5 years" business logic, and grant USAGE on this procedure to ORDER_ADMIN. The ORDER_MANAGER role owns the procedure.
Answer: D
Explanation:
This is the correct answer because it allows the ORDER_ADMIN role to perform the data cleanup without needing the DELETE privilege on the ORDERS table. A stored procedure is a feature that allows scheduling and executing SQL statements or stored procedures in Snowflake. A stored procedure can run with either the caller's rights or the owner's rights. A caller's rights stored procedure runs with the privileges of the role that called the stored procedure, while an owner's rights stored procedure runs with the privileges of the role that created the stored procedure. By creating a stored procedure that runs with owner's rights, the ORDER_MANAGER role can delegate the specific task of deleting old data to the ORDER_ADMIN role, without granting the ORDER_ADMIN role more general privileges on the ORDERS table. The stored procedure must include the appropriate business logic to delete only the records older than 5 years, and the ORDER_MANAGER role must grant the USAGE privilege on the stored procedure to the ORDER_ADMIN role. The ORDER_ADMIN role can then execute the stored procedure to perform the data cleanup12.
References:
* Snowflake Documentation: Stored Procedures
* Snowflake Documentation: Understanding Caller's Rights and Owner's Rights Stored Procedures
NEW QUESTION # 32
select metadata$filename, metadata$file_row_number from @filestage/data1.json.gz;
Please select the correct statements for the above-mentioned query.
- A. FILESTAGE is the stage name, METADATA$FILE_ROW_NUMBER will give the path to the data file in the stage
- B. FILESTAGE is the stage name, METADATA$FILE_ROW_NUMBER will give the row number for each record in the container staged data file
- C. FILESTAGE is the file name, METADATA$FILE_ROW_NUMBER will give the path to the data file in the stage
Answer: B
NEW QUESTION # 33
Snowflake recommends starting slowly with SEARCH OPTIMIZATION(i.e. adding search optimization to only a few tables at first) and closely monitoring the costs and benefits.
- A. TRUE
- B. FALSE
Answer: A
NEW QUESTION # 34
At which object type level can the APPLY MASKING POLICY, APPLY ROW ACCESS POLICY and APPLY SESSION POLICY privileges be granted?
- A. Global
- B. Schema
- C. Database
- D. Table
Answer: A
Explanation:
The object type level at which the APPLY MASKING POLICY, APPLY ROW ACCESS POLICY and APPLY SESSION POLICY privileges can be granted is global. These are account-level privileges that control who can apply or unset these policies on objects such as columns, tables, views, accounts, or users. These privileges are granted to the ACCOUNTADMIN role by default, and can be granted to other roles as needed. The other options are incorrect because they are not the object type level at which these privileges can be granted. Database, schema, and table are lower-level object types that do not support these privileges. Reference: Access Control Privileges | Snowflake Documentation, Using Dynamic Data Masking | Snowflake Documentation, Using Row Access Policies | Snowflake Documentation, Using Session Policies | Snowflake Documentation
NEW QUESTION # 35
How do Snowflake databases that are created from shares differ from standard databases that are not created from shares? (Choose three.)
- A. Shared databases will have the PUBLIC or INFORMATION_SCHEMA schemas without explicitly granting these schemas to the share.
- B. Shared databases must be refreshed in order for new data to be visible.
- C. Shared databases can also be created as transient databases.
- D. Shared databases are read-only.
- E. Shared databases cannot be cloned.
- F. Shared databases are not supported by Time Travel.
Answer: D,E,F
Explanation:
According to the SnowPro Advanced: Architect documents and learning resources, the ways that Snowflake databases that are created from shares differ from standard databases that are not created from shares are:
* Shared databases are read-only. This means that the data consumers who access the shared databases cannot modify or delete the data or the objects in the databases. The data providers who share the databases have full control over the data and the objects, and can grant or revoke privileges on them1.
* Shared databases cannot be cloned. This means that the data consumers who access the shared databases cannot create a copy of the databases or the objects in the databases. The data providers who share the databases can clone the databases or the objects, but the clones are not automatically shared2.
* Shared databases are not supported by Time Travel. This means that the data consumers who access the shared databases cannot use the AS OF clause to query historical data or restore deleted data. The data providers who share the databases can use Time Travel on the databases or the objects, but the historical data is not visible to the data consumers3.
The other options are incorrect because they are not ways that Snowflake databases that are created from shares differ from standard databases that are not created from shares. Option B is incorrect because shared databases do not need to be refreshed in order for new data to be visible. The data consumers who access the shared databases can see the latest data as soon as the data providers update the data1. Option E is incorrect because shared databases will not have the PUBLIC or INFORMATION_SCHEMA schemas without explicitly granting these schemas to the share. The data consumers who access the shared databases can only see the objects that the data providers grant to the share, and the PUBLIC and INFORMATION_SCHEMA schemas are not granted by default4. Option F is incorrect because shared databases cannot be created as transient databases. Transient databases are databases that do not support Time Travel or Fail-safe, and can be dropped without affecting the retention period of the data. Shared databases are always created as permanent databases, regardless of the type of the source database5. References: Introduction to Secure Data Sharing | Snowflake Documentation, Cloning Objects | Snowflake Documentation, Time Travel | Snowflake Documentation, Working with Shares | Snowflake Documentation, CREATE DATABASE | Snowflake Documentation
NEW QUESTION # 36
What integration object should be used to place restrictions on where data may be exported?
- A. Stage integration
- B. Storage integration
- C. Security integration
- D. API integration
Answer: B
NEW QUESTION # 37
What is a key consideration when setting up search optimization service for a table?
- A. Search optimization service works best with a column that has a minimum of 100 K distinct values.
- B. The table must be clustered with a key having multiple columns for effective search optimization.
- C. Search optimization service can significantly improve query performance on partitioned external tables.
- D. Search optimization service can help to optimize storage usage by compressing the data into a GZIP format.
Answer: A
Explanation:
Explanation:
NEW QUESTION # 38
A table, EMP_ TBL has three records as shown:
The following variables are set for the session:
Which SELECT statements will retrieve all three records? (Select TWO).
- A. SELECT * FROM identifier<Stbl_ref> WHERE NAME IN ($var1, $var2, $var3);
- B. SELECT * FROM identifier($tbl_ref) WHERE ID IN Cvarl','var2','var3');
- C. SELECT * FROM $tb1_ref WHERE $col_ref IN ($var1, Svar2, Svar3);
- D. Select * FROM Stbl_ref WHERE Scol_ref IN ('Name1','Nam2','Name3');
- E. SELECT * FROM EMP_TBL WHERE identifier(Scol_ref) IN ('Namel','Name2', 'Name3');
Answer: C,E
Explanation:
* The correct answer is B and E because they use the correct syntax and values for the identifier function and the session variables.
* The identifier function allows you to use a variable or expression as an identifier (such as a table name or column name) in a SQL statement. It takes a single argument and returns it as an identifier. For example, identifier($tbl_ref) returns EMP_TBL as an identifier.
* The session variables are set using the SET command and can be referenced using the $ sign. For example, $var1 returns Name1 as a value.
* Option A is incorrect because it uses Stbl_ref and Scol_ref, which are not valid session variables or identifiers. They should be $tbl_ref and $col_ref instead.
* Option C is incorrect because it uses identifier<Stbl_ref>, which is not a valid syntax for the identifier function. It should be identifier($tbl_ref) instead.
* Option D is incorrect because it uses Cvarl, var2, and var3, which are not valid session variables or values. They should be $var1, $var2, and $var3 instead. References:
* Snowflake Documentation: Identifier Function
* Snowflake Documentation: Session Variables
* Snowflake Learning: SnowPro Advanced: Architect Exam Study Guide
NEW QUESTION # 39
There are two databases in an account, named fin_db and hr_db which contain payroll and employee data, respectively. Accountants and Analysts in the company require different permissions on the objects in these databases to perform their jobs. Accountants need read-write access to fin_db but only require read-only access to hr_db because the database is maintained by human resources personnel.
An Architect needs to create a read-only role for certain employees working in the human resources department.
Which permission sets must be granted to this role?
- A. USAGE on database hr_db, SELECT on all schemas in database hr_db, SELECT on all tables in database hr_db
- B. MODIFY on database hr_db, USAGE on all schemas in database hr_db, USAGE on all tables in database hr_db
- C. USAGE on database hr_db, USAGE on all schemas in database hr_db, REFERENCES on all tables in database hr_db
- D. USAGE on database hr_db, USAGE on all schemas in database hr_db, SELECT on all tables in database hr_db
Answer: D
Explanation:
To create a read-only role for certain employees working in the human resources department, the role needs to have the following permissions on the hr_db database:
USAGE on the database: This allows the role to access the database and see its schemas and objects.
USAGE on all schemas in the database: This allows the role to access the schemas and see their objects.
SELECT on all tables in the database: This allows the role to query the data in the tables.
Option A is the correct answer because it grants the minimum permissions required for a read-only role on the hr_db database.
Option B is incorrect because SELECT on schemas is not a valid permission. Schemas only support USAGE and CREATE permissions.
Option C is incorrect because MODIFY on the database is not a valid permission. Databases only support USAGE, CREATE, MONITOR, and OWNERSHIP permissions. Moreover, USAGE on tables is not sufficient for querying the data. Tables support SELECT, INSERT, UPDATE, DELETE, TRUNCATE, REFERENCES, and OWNERSHIP permissions.
Option D is incorrect because REFERENCES on tables is not relevant for querying the data. REFERENCES permission allows the role to create foreign key constraints on the tables.
Reference:
: https://docs.snowflake.com/en/user-guide/security-access-control-privileges.html#database-privileges
: https://docs.snowflake.com/en/user-guide/security-access-control-privileges.html#schema-privileges
: https://docs.snowflake.com/en/user-guide/security-access-control-privileges.html#table-privileges
NEW QUESTION # 40
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